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25 April, 19:23

If a sample of helium occupies 15.9 mL at 0.885 kPa what volume will it occupy at 0.500 kPa

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  1. 25 April, 19:36
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    V2 = 28.143 mL

    28.143 mL will occupy 0.500 kpa

    Explanation:

    Let v1 = 15.9 ml

    P1 = 0.885 kpa

    P2 = 0.500 kpa

    V2=?

    Boyle's law

    Using p1v1=p2v2

    V2 = (p1v1) / (P2)

    V2 = (15.9*0.885) / 0.5

    V2 = 14.0715/0.5

    V2 = 28.143 mL
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