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27 June, 20:06

Find an equation for the nth term of the arithmetic sequence.

a19 = - 92, a20 = 6

Choices:

an = - 1856 + 98 (n - 1)

an = - 1856 - 98 (n - 1)

an = - 1856 - 98 (n + 1)

an = - 1856 + 98 (n + 1)

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Answers (1)
  1. 27 June, 21:52
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    A19 = - 92

    a20 = 6

    common difference = d = a20 - a19

    d = 6 - (-92)

    d = 6 + 92

    d = 98

    formula for nth term

    an = a1 + (n-1) d

    put n = 20

    a20 = a1 + (20-1) d

    6 = a1 + 19 (98)

    6 = a1 + 1862

    6 - 1862 = a1

    -1856 = a1

    a1 = - 1856

    now nth term:

    an = a1 + (n-1) d

    an = - 1856 + (n-1) 98

    an = - 1856 + 98 (n-1)
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