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14 August, 15:00

What's the area of a rectangle whose perimeter is 30 cm and the longest side is 4 times longer than the shortest?

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  1. 14 August, 15:58
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    Let the shortest side = X and the longer = 4X

    perimeter = (length + width) * 2

    30 = (4X + X) * 2

    30 = 8X + 2X

    30 = 10X divide 10 to both sides

    3 = X

    the longer side = 4X = 4 * 3 = 12 cm

    the shortest side = X = 3 cm

    area = length * width

    area = 3*12 = 36 cm^2

    do you understand?
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