Player B's longest home run distance is 500 ft. There ar 5,280 ft in 1 mi. How many home runs would player B need to hit at his longest distance for the total to be greater than 1 mi?

Question

Mathematics

Coby Dunlap

24 August, 07:00

Player B's longest home run distance is 500 ft. There ar 5,280 ft in 1 mi. How many home runs would player B need to hit at his longest distance for the total to be greater than 1 mi?

+2

Answers (2)

Know the Answer?

Lamont Compton · Answer 1

In order to go over one mile. player b must score over 10.56. 10.56 multiplied by 500 = 5280.

Amelie Roberson · Answer 2

The correct answer is:

11.

Explanation:

Since there are 5280 feet in 1 mile, and each home run is 500 feet, we would divide to find out how many we would need:

5280/500 = 10.56.

We cannot have 0.56 of a home run; we round this up to 11. Hitting 11 home runs at this distance would be 5500 feet, which is more than a mile.