The position of a particle s (t) = 3sin1/2t+1. So what is the average velocity of the particle for [0,3pi/2]?

From the question "The position of a particle s (t) = 3sin1/2t+1. So what is the average velocity of the particle for [0,3pi/2]?"

The equation is

s (t) = [3 sin 1] / [2t + 1]

given [0, 3pi/2] then, we can substitute it to the equation

where t = 0

and s (t) = 3pi/2

s (t) = [3 sin 1] / [2t + 1]

s (t) = [3 sin 1] / [2 (0) + 1]

s (t) = [3 sin 1] / 3

s (t) = sin 1

So the correct answer is s (t) = sin 1