Solve the following system of equations:

4x - 2y - z = - 5

x - 3y + 2z = 3

3x + y - 2z = - 5

(0, 1, 3)

(0, - 1, 3)

(0, 1, - 3)

(0, - 1, - 3)

A) 4x - 2y - z = - 5

B) x - 3y + 2z = 3

C) 3x + y - 2z = - 5

Looking at ALL 4 solutions, x = 0 in all of them.

So, let's say x = 0, eliminate the "x's" and just keep equations B and C

B) - 3y + 2z = 3

C) y - 2z = - 5

Add B) and C)

-2 y = - 2

y = 1

1 - 2z = - 5

-2z = - 6

z = 3

and x = 0