Ask Question
3 July, 11:00

The population is 25000. the population increases 3% yearly. whats the population 10 years from now

+2
Answers (2)
  1. 3 July, 11:27
    0
    Here we can find it by the formula of simple interest

    A=P*R*t:100

    A=25000*3*10:100

    A=2500*3

    A=7500

    Then the population after 10 yrs will be 25000 + 7500 = 100000
  2. 3 July, 11:55
    0
    Population in the zeroth year = 25000

    After 1 year it increases to 3%, that is 100% + 3% = 103% = 103/100 = 1.03

    So it increases by a multiplying factor of 1.03.

    At the end of year 1 = 25000*1.03

    At the end of year 2 = 25000*1.03*1.03 = 25000*1.03²

    At the end of year 3 = 25000*1.03*1.03*1.03 = 25000*1.03³

    ...

    ...

    Similarly at the end of 10 years = 25000*1.03¹⁰ evaluate with calculator.

    = 25000*1.03¹⁰ ≈ 33 597.91

    So the population at the end of 10 years will be ≈ 33 598

    Hope this explains it.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “The population is 25000. the population increases 3% yearly. whats the population 10 years from now ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers