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20 November, 07:51

What are the real root of the given power equation! 3 (x-4) 4/3 + 16=64

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  1. 20 November, 10:01
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    3 (x-4) / frac{4}{3} + 16 = 64

    The 3's cancel out so the new equation becomes 4 (x-4) + 16 = 64

    Expand the brackets

    4x - 16 + 16 = 64

    4x=64

    x = 16
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