What is the solution of the system defined by y = - x + 5 and 5x + 2y = 14?

Ax=1/3, y=11/7

Bx=4/3, y=11/3

Cx=5/11, y=0

Dx=4/3, y=1

Question

Mathematics

Princess

25 April, 21:03

What is the solution of the system defined by y = - x + 5 and 5x + 2y = 14?

Ax=1/3, y=11/7

Bx=4/3, y=11/3

Cx=5/11, y=0

Dx=4/3, y=1

+3

Answers (1)

Know the Answer?

Johnathon Lawrence · Answer 1

Y = - x + 5

5x + 2y = 14

5x + 2 (-x+5) = 14

5x - 2x + 10 = 14

3x = 14 - 10

3x = 4

x = 4/3 or 1 1/3

y = - x + 5

y = - 4/3 + 5

y = - 4/3 + (5 * 3/3)

y = - 4/3 + 15/3

y = - 4+15 / 3

y = 11/3 or 3 2/3

Correct answer is B. x = 4/3; y = 11/3

What is the solution of the system defined by y = - x + 5 and 5x + 2y = 14?Ax=1/3, y=11/7Bx=4/3, y=11/3Cx=5/11, y=0Dx=4/3, y=1

What is the solution of the system defined by y = - x + 5 and 5x + 2y = 14?

Ax=1/3, y=11/7

Bx=4/3, y=11/3

Cx=5/11, y=0

Dx=4/3, y=1