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24 April, 21:13

Will, Mike, and Sue went to dinner. Will paid 1/3 of the dinner bill. Micah and Sue paid in the ratio 2:3. If Sue paid $6 more than Will, how much did the dinner cost?

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  1. 24 April, 23:57
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    Let's call their parts w, m and s

    if will paid 1/3, then m+s=2w (they paid 2/3, which is twice as much as will did)

    Now, we know that:

    Micah and Sue paid in the ratio 2:3.

    this means the 3m=2s

    and m=2/3s

    Again:

    m+s=2w

    and we substitute m:

    2/3s+s=2w

    5/3s=2w / / multiply both sides by 3

    5s=6w

    we also know that s=w+6 (from the last sentence) so we substitute:

    5 (w+6) = 6w

    5w+30=6w

    30=w

    so, Will paid 30, Sue paid 36 (six more than him), Mike paid 24 (24:36 is the same ratio as 2:3, you can check this by dividing both 24 and 36 by 12: you have 2 and 3)

    and the total was 30+36+24=90.
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