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29 August, 16:55

How is 6 a solution for 2x^2+4x=3+3x^2

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  1. 29 August, 19:37
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    2x^2+4x-3-3X^2=0

    simplify 2x^2+4x-3-3x^2 to - x^2+4x-3

    -x^2+4x-3=0

    Multiply both sides by - 1

    x^2-4x+3=0

    Factor x^2-4x+3

    1. Ask: Which two number add up to - 4 and multiply to 3.

    2. Answer:3 and - 1.

    3. Rewrite the expression as (x-3) (x-1):

    (x-3) (x-1) = 0

    5Solve for x

    1. Ask: when will (x-3) (x-1) equal zero.

    2. Answer: when x-3=0 or x-1=0.

    x=3,1
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