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27 March, 00:24

Write an equation in slope-intercept form of a line with the following characteristics: parallel to the graph of: - 4x + 3y = 12 and passes through the origin.

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  1. 27 March, 02:28
    0
    The line that's already there: - 4x + 3y = 12

    Add 4x to each side: 3y = 4x + 12

    Divide each side by 3 : y = 4/3 x + 4

    The line that's already there has a slope of 4/3.

    Any line parallel to it has the same slope but different y-intercept.

    If the new line passes through the origin, then its y-intercept is zero.

    The equation of the new line is y = 4/3 x
  2. 27 March, 02:42
    0
    Slope of given line is m=-a/b = 4/3

    So searched equation is:

    y-0=4/3 (x-0)

    y = 4/3x
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