Identify the vertex, axis of symmetry, min/max value, and range of each. Y=-10x20x-15

I will assume you meant y=-10 (x^2) + 20x-15

In which case to find the vertex you would do - b/2a

So for this one that would be - 20/-20 which is just 1, that is the x value of the vertex so to find the y value you plug 1 into the equation and get 5 so the

Vertex is (1,5)

Since the a value is negative the equation will have a max value and that value will be the same as the y value of the vertex.

Max value: y=5

Axis of symmetry is the x value of the vertex

Axis of symmetry: x=1

The range is all possible y values so in this case it is from the y value of the vertex and down

Range: y

Domain is all possible x values which is all real numbers for every quadratic.

In summary:

Vertex is (1,5)

Axis of symmetry: x=1

Max value: y=5

Range: y<5

Domain: all real numbers