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4 September, 03:36

Solve for the variable: 3 (q-5) = 2 (q+5)

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  1. 4 September, 06:35
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    Distribute

    a (b+c) = ab+ac or

    a (b-c) = ab-ac

    so

    3 (q-5) = 3q-15

    2 (q+5) = 2q+10

    3q-15=2q+10

    minus 2q from both sides

    q-15=10

    add 15 to both sides

    q=25
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