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5 October, 12:08

A man has 43 coins, All nickels, dimes & quarters. He has one more than three times as many dimes as he does nickels and twice as many quarters as he does nickels.

How many of each coin does he have?

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  1. 5 October, 13:47
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    1 + 3d = n = > (n-1) / 3 = d

    2n = q

    n + d + q = 43

    substitute

    n + (n-1) / 3 + 2n = 43

    n = 13

    q = 26

    d = 4
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