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31 January, 02:53

4x+5y=3

-7x-6y=-19

To eliminate x we must find the least common multiple of 4 and 7. What is it?

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  1. 31 January, 05:35
    0
    7 is prime so multiply them

    4*7=28

    answer is 28

    anyway, multiply top by 7 and bottom by 4 to add to get

    28x+35y=21

    -28x-24y=-76 +

    0x+11y=-55

    11y=-55

    divide by 11

    y=-5

    sub back

    4x+5y=3

    4x+5 (-5) = 3

    4x-25=3

    add 25

    4x=28

    divde 4

    x=7

    (7,-5)
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