The cost of 12 oranges and 7 apples is $5.36. eight oranges and 5 apples cost $3.68. Find The cost of each

Orange=x

apple=y

12x + 7y = 5.36

8x + 5y = 3.68

Now, we can do simultaneous equation to get answer

First, we have to find the same value for one of these numbers

60x + 35y = 26.8

-56x - 35y = - 25.76

Then, add two equations to get new equation

4x = 1.04

and one equation from the begining

4x = 1.04

8x + 5y = 3.68

then divide 1.04 with 4 from the first equation to get value of x

x = 0.26

8x + 5y = 3.68

Then just change x with number 0.26 in the second equation.

x = 0.26

8 * 0.26 + 5y = 3.68

x=0.26

2.08 + 5y = 3.68

x=0.26

5y = 3.68 - 2.08

x=0.26

5y = 1.6

x=0.26

y=0.32

Oranges=r

apples=a

12r+7a=5.36

-12r - 12r

What you do on one side you do on both sides

12 on the left cancels out

7a=5.36-12r

/7 / 7 / 7

Divide 7

7 on the left cancels out

5.36/7=0.76 ...

left with

a=0.76-12r/7

so the apples cost $0.76 each

to get the cost of the oranges (r) you do the same as you did to get the cost of the apples.

Also on the other equation for 8 oranges and 5 apples you might get different answers but you will see that they are close/similar to the same answers as you will get for the last equations.