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18 November, 21:22

How does the graph of f (x) = 5 cos (1/2x) - 2 differ from the graph of g (x) = 5 cos (x) - 2

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  1. 18 November, 21:37
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    F (x) = 5cos (1/2x) - 2

    g (x) = 5cos (x) - 2

    The period for a cosine function is 2pi/k

    In the equation the k is located before the variable.

    In g (x) we have 5cos (1x) - 2

    so the period is 2pi/1 or 2pi. This means the length of one full period of cosine will go from 0 to 2pi.

    In f (x) we have 5 cos (1/2 x) - 2

    so the period is 2pi / (1/2) which is the same as 2pi * 2 or 4pi.

    This means the period for the function is 4pi and the length of one full period of the cosine graph will go from 0 to 4pi.

    The length of f (x) will be longer than that of g (x).
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