The mean of six numbers is 41. If one number is removed, the mean of the five numbers is 46. Find the unknown number.

Mean of 6 numbers is 41 means

(x+y+z+t+a+b) / 6=41

(x+5morenumbers) / 6=41

if 1 is removed (say x)

mean iof 5 numbers is 46

(5morenumbers) / 5=46

multiply first equaiton by 6 and second eqiaton by 5 to clear fractions

x+5morenumbers=246

5morenumbers=230

sub 230 for 5morenumbers in first equaiton

x+230=246

minus 230 both sides

x=16

the unknown is 16