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28 November, 18:38

What is the angle between the given vector and the positive direction of the x-axis 8i 6j?

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  1. 28 November, 20:15
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    The given vector is

    8i + 6j

    The angle can be calculated using

    θ = tan⁻¹ (b/a)

    where b and a are determined from

    ai + bj

    θ = tan⁻¹ (6/8) = 36.9 degrees

    The angle between the vector and the positive x-direction is 36.9 degrees.
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