Function f (z) = 2z - (3+i)

Find the:

second iterate for z0=i

third iterate for z0=3-i

first iterate for z0=0.5+i

third iterate for z0=-2-5i

F (z) = 2z - (3+i)

1) second interate for z0 = i

first iterate = f (z0) = f (i) = 2i - 3 - i = i - 3 = z1

second iterate = f (z1) = f (i-3) = 2 (i-3) - 3 - i = 2i - 6 - 3 - i = i - 9

2) third iterate for z0 = 3 - i

first iterate = f (z0) = f (3 - i) = 2 (3-i) - (3+i) = 6 - 2i - 3 - i = 3 - 3i = z1

second iterate = f (z1) = f (3 - 3i) = 2 (3-3i) - (3+i) = 6 - 6i - 3 - i = 3 - 7i = z2

third iterate = f (z2) = f (3 - 7i) = 2 (3-7i) - (3+i) = 6 - 14i - 3 - i = 3 - 15i = z3.

3) first iterate for z0=0.5+i

first iterate = f (z0) = f (0.5 + i) = 2 (0.5+i) - (3+i) = 1 + 2i - 3 - i = - 2 + i = z1

4) third iterate for z0=-2-5i

first iterate = f (z0) = 2 ( - 2 - 5i) - (3 + i) = - 4 - 10i - 3 - i = - 7 - 11i = z1

second iterate = f (z1) = 2 ( - 7 - 11i) - (3+i) = - 14 - 22i - 3 - i = - 17 - 23i = z2

third iterate = f (z2) = 2 (-17-23i) - (3+i) = - 34 - 46i - 3 - i = - 37 - 47i = z3