If the dimensions of a cylinder are doubled, then its volume is quadrupled. Which I know is false.

But my question is what is the dimensions of its volume going to be, doubled? I'm getting ready for my test.

Suppose we have a cylinder with radius r1 and height h1. The volume of this cyliner would be calculated as:

V1 = pi (r1^2) h1

If the measurements are being doubled then r2=2r1 and h2=2h1. The volume would change as follows:

V2 = pi (r2^2) h2

V2 = pi ((2r1) ^2) 2h1

V2 = pi (4) (r1) ^2) 2h1

V2 = 8 pi (r1) ^2) h1

V2 = 8 V1