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16 March, 13:14

Find tan _ if sec _ = square root of thirty seven divided by six and sin _ < 0.

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  1. 16 March, 16:58
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    Identity: sec^2 (x) = 1 + tan^2 (x) = > tan^2 (x) = sec^2 (x) - 1

    sec (x) = √[37/6] = > sec^2 (x) = 37/6

    tan^2 (x) = 37/6 - 1 = 31/6

    tan (x) = + / - √[31/6]

    Given that sin (x) is negative and sec (x) is positive, we are in the fourth quadrant, so the tangent is negative, then:

    tan (x) = - √[31/6] = - 2.27
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