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21 February, 19:30

2n^2+3n-9 factored completely

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  1. 21 February, 20:53
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    We take the factors of 2 ... 2 and 1

    factors of - 9 ... - 3 and 3

    multiply the first numbers we get - 6 and second numbers are 3. when we subtract them, we get our middle term of - 3.

    (2n - 3) (n + 3)
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