What is the discriminant in the quadratic equation x2 + 11x + 121 = x + 96?

A. 0 B. 100 C. 20 D. 200

Given:

x² + 11x + 121 = x + 96

First, we need to convert it into a quadratic equation.

x² + 11x - x + 121 - 96 = 0

x² + 10x + 25 = 0

a = 1; b = 10; c = 25

Quadratic formula:

x = (-b + (√b² - 4ac)) : 2a

The discriminant is under the radical sign

discriminant ⇒ b² - 4ac ⇒ 10² - 4 (1) (25) ⇒ 100 - 100 = 0

Correct answer is A. 0