Radiochemical techniques are useful in estimating the solubility product of many compounds. In one experiment, 70.0 mL of 0.030 M AgNO3 solution containing a silver isotope with a radioactivity of 74,025 counts per min per mL were mixed with 300.0 mL of a 0.080 M NaIO3 solution. The mixed solution was diluted to 700.0 mL and filtered to remove all of the AgIO3 precipitate. The remaining solution was found to have a radioactivity of 44.4 counts per min per mL.

Question

Mathematics

Ruth Price

6 April, 12:58

Radiochemical techniques are useful in estimating the solubility product of many compounds. In one experiment, 70.0 mL of 0.030 M AgNO3 solution containing a silver isotope with a radioactivity of 74,025 counts per min per mL were mixed with 300.0 mL of a 0.080 M NaIO3 solution. The mixed solution was diluted to 700.0 mL and filtered to remove all of the AgIO3 precipitate. The remaining solution was found to have a radioactivity of 44.4 counts per min per mL.

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Greta Wilson · Answer 1

Given:

V1 = 70 ml

C1 = 0.030 M AgNO3 solution

Radioactivity: 74,025 counts/min mL

V2 = 300 ml

C2 = 0.080 M NaIO3

Balanced Equation:

AgNO3 + NaIO3 = = > NaNO3 + AgIO3

Then the solution is diluted to 700 ml, the dilution factor is (300 + 70) / 700. This will be used in calculating the solubility of the product.