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19 November, 04:20

Paulina invested $10,000 at two different rates, 4% and 6%. If her total interest income was $470, how much did she invest at each rate.

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  1. 19 November, 07:46
    0
    A+b=10000 (1)

    4%a+6%b = 470

    4a+6b = 47000 (2)

    (1) * 6 = >

    6a+6b = 60000 (3)

    (3) - (2) = >

    2a=13000 = >

    a = 6500

    b = 3500
  2. 19 November, 07:49
    0
    0.04x+0.06 (10000-x) = 470

    Solve for x

    X=6500 at 4%

    10000-6500=3500 at 6%
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