Given that a=43, b=82, and c=28, solve triangle abc. round to the nearest tenth.

Given a triangle with sides:

a = 43

b = 82

c = 28

The perimeter of the triangle ABC is 153 units.

The angles of the triangle can be determined by cosine law

a^2 = b^2 + c^2 - 2bccosA

and the other angles can be determined using sine law

sin A / a = sin B / b = sin C / c