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15 October, 11:15

The length of a rectangle is 5 yd longer than its width. If the perimeter of the rectangle is 38 yd, find its area.

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  1. 15 October, 13:01
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    L=5+W

    P=2 (L+W)

    38=2 (L+W)

    divide by 2

    19=L+W

    sub 5+W for L

    19=5+W+W

    19=5+2W

    minus 5 both sides

    14=2W

    divid both sides by 2

    7=W

    L=5+W

    L=5+7

    L=12

    area=LW

    are=12 times 7

    area=84 yd²
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