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8 January, 03:36

What is the value of 81x2y3+z if x=3 y=4 and z=19

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  1. 8 January, 07:27
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    Ok first of all I am assuming you mean

    81. (x**2). (y**3) + z = Value

    We just need to simply substitute x, y and z

    81. (3*3) (4*4*4) + 19 = Value

    46656 + 19 = Value ... >> Value = 46675
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