A new neighborhood activity complex is being built in del rio. the perimeter of the rectangular playing field is 272 yards. the length of the field is 5 yards less than double the width. what are the dimensions of the playing field?

Let the width be x, double the width is 2x, then the length is 2x - 5

Perimeter = 2 (l + w) = 2 (2x - 5 + 2x) = 2 (4x - 5) = 8x - 10 = 272

8x = 272 + 10 = 282

x = 282/8 = 35.25

Therefore, width is 35.25 yards and length is 2 (35.25) - 5 = 65.5