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11 November, 13:53

5 (2m+3) - 1 (1-2m) = 2[3 (3+2m) - (3-m) ]

Can you solve for the variable m?

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Answers (2)
  1. 11 November, 14:19
    0
    You could start by doing distributive property then getting like terms together
  2. 11 November, 15:42
    0
    10m + 15 - 1 + 2m = 2 [ 9 + 6m - 3 + m]

    12m + 14 = 18 + 12m - 6 + m

    12m + 14 = 12 + 13m

    12m - 13m = 12 - 14

    -m = - 2

    m = 2
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