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20 December, 07:51

5y+3x=13/2

y=-5x+57/10 steps

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Answers (1)
  1. 20 December, 08:32
    0
    Express the system in standard form:

    {3 x + 5 y = 13/2 | (equation 1)

    {5 x + y = 57/10 | (equation 2)

    Swap equation 1 with equation 2:

    {5 x + y = 57/10 | (equation 1)

    {3 x + 5 y = 13/2 | (equation 2)

    Subtract 3/5 * (equation 1) from equation 2:

    {5 x + y = 57/10 | (equation 1)

    {0 x + (22 y) / 5 = 77/25 | (equation 2)

    Multiply equation 1 by 10:

    {50 x + 10 y = 57 | (equation 1)

    {0 x + (22 y) / 5 = 77/25 | (equation 2)

    Multiply equation 2 by 25/11:

    {50 x + 10 y = 57 | (equation 1)

    {0 x+10 y = 7 | (equation 2)

    Divide equation 2 by 10:

    {50 x + 10 y = 57 | (equation 1)

    {0 x+y = 7/10 | (equation 2)

    Subtract 10 * (equation 2) from equation 1:

    {50 x+0 y = 50 | (equation 1)

    {0 x+y = 7/10 | (equation 2)

    Divide equation 1 by 50:

    {x+0 y = 1 | (equation 1)

    {0 x+y = 7/10 | (equation 2)

    Collect results:

    Answer: {x = 1

    {y = 7/10
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