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30 May, 09:25

Find the solutions to the equation sin2x=square root of 3 cos2x

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  1. 30 May, 12:08
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    Sin2x=square root (3) * cos2x

    sin (2x) / cos (2x) = square root of 3

    tan (2x) = square root of 3

    tan (x) = square root of 3 when y=pi/3+pi*n

    tan (2x) = square root of 3 when y=pi/6+pi*n

    {x:x=pi/3+pi*n, where n is an element of the integers}
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