Find the solutions to the equation sin2x=square root of 3 cos2x

Sin2x=square root (3) * cos2x

sin (2x) / cos (2x) = square root of 3

tan (2x) = square root of 3

tan (x) = square root of 3 when y=pi/3+pi*n

tan (2x) = square root of 3 when y=pi/6+pi*n

{x:x=pi/3+pi*n, where n is an element of the integers}