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19 October, 17:49

A certain number is 3 more than twice another. If their sum is increased by 8, the result is 41. Find the numbers.

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  1. 19 October, 19:24
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    X = 2y + 3

    (x + y) + 8 = 41

    (2y + 3 + y) + 8 = 41

    3y + 11 = 41

    3y = 41 - 11

    3y = 30

    y = 30/3

    y = 10

    x = 2y + 3

    x = 2 (10) + 3

    x = 23

    ur numbers are 10 and 23
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