A certain number is 3 more than twice another. If their sum is increased by 8, the result is 41. Find the numbers.

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Mathematics

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19 October, 17:49

A certain number is 3 more than twice another. If their sum is increased by 8, the result is 41. Find the numbers.

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Answers (1)

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Lamar Rojas · Answer 1

X = 2y + 3

(x + y) + 8 = 41

(2y + 3 + y) + 8 = 41

3y + 11 = 41

3y = 41 - 11

3y = 30

y = 30/3

y = 10

x = 2y + 3

x = 2 (10) + 3

x = 23

ur numbers are 10 and 23