A ship leaves port at 1:00 p. m. and travels s35°e at the rate of 26 mi/hr. another ship leaves the same port at 1:30 p. m. and travels s20°w at 20 mi/hr. approximately how far apart are the ships at 3:00 p. m.?

Question

Mathematics

Patience Deleon

16 September, 20:33

A ship leaves port at 1:00 p. m. and travels s35°e at the rate of 26 mi/hr. another ship leaves the same port at 1:30 p. m. and travels s20°w at 20 mi/hr. approximately how far apart are the ships at 3:00 p. m.?

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Aaron Bolton · Answer 1

We need to use the distance formula for this problem. d = sqrt[ (x2 - x1) ^2 + (y2 - y1) ^2] We need to find these values. d = (52) ^2 + (30) ^2 Thus, these ships are approximately sqrt (3604) = about 60 miles apart.