Which equation is y=6x^2+12-10 rewritten in vertex form

The formula in order to obtain the vertex form of a quadratic equation is given as

y=a (x-h) ^2+k where (h, k) is the vertex of the quadratic equation which is parabolic in shape and it is opening upward.

As given in the problem, y=6x^2+12x-10

Using the formula, we can transformed the quadratic equation y=6x^2+12x-10 into its vertex form:

y=6x^2+12x-10

y = (6x^2+12x) - 10 (grouping)

y=6 (x^2+2x) - 10 (factoring Common terms per group)

y=6 (x^2+2x+1) - 10-6 (Completing the squares)

y=6 (x+1) ^2-16 (Factor and Simplify)

Hence, the vertex form of y = 6x^2+12x-10 is y=6 (x+1) ^2-16