Using the discriminant, what values of c will make the quadratic y = 2x2 - 3x + c have one real solution?

The discriminant is b^2-4ac in the equation ac^2+bx+c

so taking 2x^2-3x+c we have discrimant of

(-3) ^2-4 (2) c which simplifies to 9-8c

one real solution happens when the discrimnant is 0 so we have

9-8c=0 so 9=8c and c=9/8

so when c is 9/8 we will have 1 real solution

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