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12 April, 14:50

Suppose each runner ran at the rate given in the table above for 3.1 miles. How much time will elapse between the first place finisher and the last place finisher?

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  1. 12 April, 15:59
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    You didn't include the table but I found this table for the same statement, so I will answer you based on the next table:

    Runner distance time

    Arabella 7,299 feet 561 seconds

    Bettina 3,425 yards 13 minutes, 12 seconds

    Chandra 8,214 feet 0,195 hours

    Divya 1,62 miles 732 seconds

    To answer the question you must find the rate for each runner and then calculate the time to run 3.1 miles at each rate.

    First you need to convert the data to obtain the rate in miles per second.

    These are the main conversion identities:

    1 mile = 5280 feet

    1 mile = 1760 yards

    1 hour = 3600 seconds

    1 hour = 60 minutes

    1 minute = 60 seconds

    Arabella:

    rate: 7,229 feet / 561 seconds * (1 mile / 5280 feet) =

    = 0.00244 mile/second

    Time to run 3.1 miles: V = d / t = > t = d / V = 3.1 miles / 0.00244 mile/second = 1270 seconds

    Bettina:

    13 minutes + 12 seconds = 13*60 seconds + 12 seconds = 792 seconds

    rate = 3425 yards / 792 seconds * 1 mile / 1760 yards = 0.00246 mile/seconds

    Time to run 3.1 miles = 3.1 miles / 0.00246 mile/second = 1260 seconds

    Chandra:

    rate = 8214 feet / 0.195 hours * 1 mile / 5280 feet * 1hour / 3600 seconds =

    = 0.00222 seconds

    Time = 3.1 mile / 0.00222 seconds = 0.389 hour = 1396 seconds

    Divya:

    rate = 1.62 miles / 732 seconds = 0.00221 seconds

    Time = 3.1 mile / 0.00221 seconds = 1403 seconds

    Now you can find the difference between fhe last and the first 1403 seconds - 1260 seconds = 143 seconds

    That is equivalent to 2.38 seconds.
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