Find the magnitude and direction angle for the vector v=6cos137degrees i+6sin137degrees j.

A.) 6,137 degrees

B.) 6,43 degrees

C.) 6squareroot of 2, 43 degrees

D.) 6squareroot of 2, 137 degrees

The vector in its generic form is given by:

v = lvl * (cos (theta) i + sin (theta) j)

Where,

lvl: magnitude of the vector

theta: direction angle

We have the following vector:

v = 6cos137degrees i + 6sin137degrees j.

Rewriting:

v = 6 (cos137degrees i + sin137degrees j)

Thus,

lvl = 6

theta = 137 degrees

Answer:

The magnitude and direction angle for the vector are:

A.) 6,137 degrees