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6 January, 01:07

Complete the solution of the equation. find the value of y when x equals 11 8x+6y=28

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Answers (2)
  1. 6 January, 02:34
    0
    First, substitute the value of x back into the equation.

    8x + 6y = 28 becomes 8 (11) + 6y = 28

    Now solve for y.

    8 (11) + 6y = 28

    88 + 6y = 28

    6y = - 60 < - - Subtract 88 from each side

    y = - 10 < - - Divide both sides by 6

    So, y is equal to - 10.
  2. 6 January, 03:08
    0
    If x is 11, then we replace x with 11 in the equation.

    8 (11) + 6y = 28

    88 + 6y = 28

    We will subtract 88 from both sides to get rid of the constant.

    6y = - 60

    To isolate the variable, we will divide both sides by 6.

    y = - 10

    In this equation, y equals - 10.
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