The height of a ball thrown directly up with a velocity of 10 feet per second from a initial height of of 100 feet is given by the equation h (t) = - 16tsquared + 10t + 100, where t is the time in seconds and h is the ball's height, measured in feet. When will the ball hit the ground? Round your answer to the nearest tenth.

Question

Mathematics

Shannon George

13 November, 06:20

The height of a ball thrown directly up with a velocity of 10 feet per second from a initial height of of 100 feet is given by the equation h (t) = - 16tsquared + 10t + 100, where t is the time in seconds and h is the ball's height, measured in feet. When will the ball hit the ground? Round your answer to the nearest tenth.

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Answers (1)

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Hunter Friedman · Answer 1

The ball will hit the ground when h (t) = 0 so:

-16t^2+10t+100=0

Using the quadratic equation:

t = (-10±√6500) / - 32, and since t>0

t≈2.8 seconds (to nearest tenth of a second)