What are the phase shift and period for the function y = 3cos[4 (θ + 60°) ] - 2?

Phase shift = right 60°, period = 90°

Phase shift = right 60°, period = - 90°

Phase shift = left 60°, period = 90°

Phase shift = left 60°, period = - 90°

Question

Mathematics

Rory Murphy

9 March, 12:52

What are the phase shift and period for the function y = 3cos[4 (θ + 60°) ] - 2?

Phase shift = right 60°, period = 90°

Phase shift = right 60°, period = - 90°

Phase shift = left 60°, period = 90°

Phase shift = left 60°, period = - 90°

+1

Answers (1)

Know the Answer?

Shiloh Rollins · Answer 1

The plus sign inside the parenthesis indicates that the shift is to the left, And the formula for the period is 2pi/B and our B is 4, so 2pi/4 = pi/2 which is 90. So your answer is the third one down, left 60 period 90

What are the phase shift and period for the function y = 3cos[4 (θ + 60°) ] - 2?Phase shift = right 60°, period = 90°Phase shift = right 60°, period = - 90°Phase shift = left 60°, period = 90°Phase shift = left 60°, period = - 90°

What are the phase shift and period for the function y = 3cos[4 (θ + 60°) ] - 2?

Phase shift = right 60°, period = 90°

Phase shift = right 60°, period = - 90°

Phase shift = left 60°, period = 90°

Phase shift = left 60°, period = - 90°