How many different ways can a club choose a committee of 4 from 15 members?

a. 32,760

b. 1,365

c. 24

It is done by this formula

combinations = n! / [r! * (n - r) !]

combinations = 15! / [4! * 11!]

combinations = 15 * 14 * 13 * 12 * 11! / [4! * 11!]

combinations = 15 * 14 * 13 * 12 / 4 * 3 * 2

combinations = 15 * 7 * 13

combinations = 1,365

answer is b

To find this, we'd do 15*14*13*12, which equals A: 32,760