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16 June, 17:59

If the area of a rectangle is 16s^2t and the length is 8st^2, what would be the width of the rectangle, given that width is found by dividing area by length? Simplify the answer.

2st

2 over the quantity s times t

the quantity of 2 times s all over t

t over the quantity 2 times s

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  1. 16 June, 20:51
    0
    Given:

    Area = 16s²t

    Length = 8st²

    Width = ?

    Width = Area / Length

    Width = 16s²t / 8st²

    Width = 2s/t ⇒ the quantity of 2 times s all over t.
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