If the area of a rectangle is 16s^2t and the length is 8st^2, what would be the width of the rectangle, given that width is found by dividing area by length? Simplify the answer.

2st

2 over the quantity s times t

the quantity of 2 times s all over t

t over the quantity 2 times s

Question

Maverick Barry

16 June, 17:59

+4

Answers (1)

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Toby · Answer 1

Given:

Area = 16s²t

Length = 8st²

Width = ?

Width = Area / Length

Width = 16s²t / 8st²

Width = 2s/t ⇒ the quantity of 2 times s all over t.

If the area of a rectangle is 16s^2t and the length is 8st^2, what would be the width of the rectangle, given that width is found by dividing area by length? Simplify the answer.2st2 over the quantity s times tthe quantity of 2 times s all over tt over the quantity 2 times s