Ask Question
27 December, 13:05

A metallurgist has an alloy with 10% titanium and an alloy with 20% titanium. he needs 100 grams of an alloy with 17% titanium. how much of each alloy should be mixed to attain the 100 grams of alloy with 17% titanium?

+5
Answers (1)
  1. 27 December, 17:04
    0
    Let us say that:

    x = mass of 10% titanium alloy required

    y = mass of 20% titanium alloy required

    To solve this problem, we set-up two mass balances or equations.

    Overall mass balance: x + y = 100

    x = 100 - y - - - > 1

    Titanium mass balance: 0.10 x + 0.20 y = 0.17 (100)

    0.10 x + 0.20 y = 17 - - - > 2

    Now we combine equations 1 and 2:

    0.10 (100 - y) + 0.20 y = 17

    10 - 0.10 y + 0.20 y = 17

    0.10 y = 7

    y = 70 g

    Calculating for x using equation 1:

    x = 100 - y

    x = 100 - 70

    x = 30 g

    Answer:

    x = 30 g of 10% titanium alloy required

    y = 70 g of 20% titanium alloy required
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A metallurgist has an alloy with 10% titanium and an alloy with 20% titanium. he needs 100 grams of an alloy with 17% titanium. how much of ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers