Ned walks 6/10 of a mile to school. Fred walks 9/15 of a mile to school. Who walks farther?

Question

Mathematics

Wesley Murphy

19 November, 06:29

Ned walks 6/10 of a mile to school. Fred walks 9/15 of a mile to school. Who walks farther?

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Answers (2)

Know the Answer?

Dangelo Taylor · Answer 1

6/10 of a mile would be 3168 feet. 9/15 of a mile would be 3168 feet as well. So therefore, they walked the same distance

Cynthia Benton · Answer 2

There are a few ways to solve the problem. I will use 2 ways. You can use equivalent fractions.

Way 1:

You find the LCM of 10 and 15.

10: 10,20,30,40,50

15: 15,30,45,60,75

LCM of 10 and 15: 30

30/10=3

6*3=18

6/10=18/30

30/15=2

9*2=18

9/15=18/30

18/30=18/30

Since 6/10=9/15, Ned and Fred walked the same miles to school.

Way 2:

You could simplify 6/10 into 3/5 and simplify 9/15 into 3/5 by using GCF and since 3/5=3/5, 6/10=9/15. Since 6/10=9/15, Ned and Fred walked the same miles to school.