Find the volume of the solid formed by revolving the region bounded by the graphs of y = x^2, x = 3, and y = 4 about the y-axis.

25 times pi divided by 2

97 times pi divided by 3

173 times pi divided by 3

None of these

X=3 and y=x^2 intersect at (3,9), so your bounds are y=4 and y=9 and and., so you use the disk method therefore you have to switch variables (even though x^2 is not invertible, because you only need the right side you can use y^ (1/2)) so pi*integral (3^2 - (y^ (1/2)) ^2 dy) making it pi*[9y - (1/2) y^2]|y = (4,9), pi*[25/2]