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28 June, 21:31

What is the exact solutions of x2=5x+2

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  1. 28 June, 22:39
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    Move all terms to the left of equal with changed sign

    x²-5x-2 = 0

    Solve with x₁,₂ = (-b±√Δ) / 2a

    Δ = b²-4ac

    call a (1) x², b - 5 and c - 2

    x1,2 = ( - (-5) ±√ (-5) ²-4*1 * (-2)) / 2*1

    x1,2 = (5±√25+8) / 2

    x1,2 = (5 ± √33) / 2

    x1 = (5+√33) / 2

    x2 = (5-√33) / 2
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