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29 April, 01:35

Kelly tells you that when variables are in the denominator, the equation becomes unsolvable. "There is a value for x that makes the denominator zero, and you can't divide by zero," Kelly explains. Using complete sentences, demonstrate to Kelly how the equation is still solvable.

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  1. 29 April, 04:17
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    The problem can be translated into an equation that is something like 4/5 + 3/x = 1/2

    we cannot have x equal to zero because the number can be infinite.

    So the LCD here is 10x, so multiply both sides by that to get:

    8x + 30 = 5x

    Subtract 5x and 30 from both sides:

    3x = - 30

    divide:

    x = - 10

    The solution isn't zero so there is a solution.
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